An organic compound was found to contain only C, H, and Cl. When a 1.50-g sample of the compound was completely combusted in air, 3.52 g of CO was formed. In a separate experiment the chlorine in a 1.00-g sample of the compound was converted to 1.27 g of AgCl. Determine the empirical formula of the compound.

Hence the emperical formula for the compound will be C6H5Cl  

Explanation:

solution:

To Calculate the mass of Carbon atom in CO2 and Chlorine in AgCI and Hydrogen atom from the sample  

Mass of Carbon in 3.52 g of CO2 = (3.52 Molar Mass of CO2)* Molar Mass of Carbon atom =(3.52/44) *12 = 0.96g  

Similarly Mass of Chlorine and Hydrogen can be calculated.

1.27 Mass of Chlorine = (1.27/143.25)*35.45 = 0.314g  

Mass of Hydrogen = Mass of the sample - Mass of Carbon and Chlorine

                               = 1.50-0.96 + 0.314g

                               = 0.069g  

Now Calculating the number of moles of each 0.96

Number of moles of Carbon = 0.96/12 = 0.08 moles

Number of moles of Chlorine = 0.314/35.5=0.013 moles  

Number of moles of Hydrogen = 0.069/1.01=0.068 moles

Dividing each of the obtained moles by 0.013 we get the integer numbers i.e 0.08/0.013 = 6 , 0.013/0.013 = 1 , 0.068/0.013 = 5.  

Hence the emperical formula for the compound will be C6H5Cl  

i don't understand. explain it clearly

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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