How much current is flowing in a wire 4.55 m long if the maximum force on it is 0.575 N when placed in a uniform 0.0700-T field?

1.81A

The magnitude of the magnetic force (F) acting on a current carrying wire is given by;

F = I x L x B sin θ      (i)

Where;

I = current on the wire

B = magnetic strength

L = length of the wire

θ = angle between the wire and the magnetic field

From the question, there is a maximum force (F = 0.575N) of on the wire. This means that the angle between the wire and the magnetic field is 90°.

Also;

the magnetic field(B) = 0.0700-T

the length(L) of the wire = 4.55m

Substitute these values into equation (i) as follows;

0.575 = I x 4.55 x 0.0700 x sin 90°

0.575 = I x 4.55 x 0.0700 x 1

0.575 = I x 0.3185

Solve for I;

I = 0.575 / 0.3185

I = 1.81A

Therefore, the current flowing in the wire is 1.81A

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

i believe it is b. what was the cause of the big bang

hope this !