Calculate the work (in joules) required to pump all of the liquid out of a full tank. Assume a=6 m, b=12 m, liquid exits through the spout, c=3 m, and density of the liquid is 1000 kg/m3. (Use decimal notation. Give your answer to two decimal place.)

Explanation:

From the expression of workdone, we no that

Workdone= force * distance

also  

force=pressure *area

since pressure = density*height* gravity

we have

work done=pressure * area * distance

from the question, the workdone will be a dependent function on the height

hence we can write

to get the absolute workdone, we have to integrate both sides

Hence we have

if the forces acting on an object are unbalanced, the object will accelerate in the direction of the net force on the object.

explanation:

this is best explained by having an understanding of newton's second law, which states that f=ma. you see, when the forces are unbalanced, net force (sum of all forces) is not zero. therefore making it necessary for the object to have an acceleration in the direction of the net force.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer