Object A and object B are initially uncharged and are separated by a distance of 1 meter. Suppose 10,000 electrons are removed from object A and placed on object B, creating an attractive force between A and B. An additional 10,000 electrons are removed from A and placed on B and the objects are moved so that the distance between them increases to 2 meters. By what factor does the electric force between them change?

1

Explanation:

Let's call the magnitude of the charge of 10000 electrons .

Because A loses q, it has a net charge (electrons are negative; losing them creates positive charges). Conversely, B has gained q, so it has a charge of . The distance between them is 1 m.

By Coulomb's law, the force between them is

When A loses an additional 10000 electrons, the charge on it becomes while that on B is . The distance is now 2 m.

The force is now

6/12=1/2

step-by-step explanation: