A nonconducting wall carries a uniform charge density of 10.81 µC/cm2 . What is the electric field 4.8 cm in front of the wall? The permittivity of a vacuum is 8.8542 × 10−12 C 2 /N · m2 . Answer in units of N/C.

To solve this problem it is necessary to apply the concepts related to electric field due to non conducting wall. This is defined as

We have that

is the charge per unit area of the wall and the vacuum permittivity

First we need to convert to SI Units,

Now replacing we have,

Therefore the electric field is

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm