Tom has two pendulums with him. Pendulum 1 has a ball of mass 0.2 kg attached to it and has a length of 5 m. Pendulum 2 has a ball of mass 0.6 kg attached to a string of length 1 m. How does mass of the ball affect the frequency of the pendulum? The mass of the ball of the pendulum is inversely proportional to the period; hence it will affect the frequency of the pendulum. The mass of the ball of the pendulum will not affect the period; hence it will not affect the frequency of the pendulum. The mass of the ball of the pendulum is directly proportional to the period; hence it will affect the frequency of the pendulum. The mass of the ball of the pendulum is directly proportional to the square of the period; hence it will affect the frequency of the pendulum. Which pendulum will have a higher frequency and why?

A.

The mass of the ball of the pendulum will not affect the period; hence it will not affect the frequency of the pendulum.

B.

Pendulum 2.

Explanation:

A.

The mass of the bob of a pendulum is not relevant to its period of oscillation. Its length of the of the pendulum is.

B.

T = 2pi*sqrt(L/g)

For pendulum 1,

L = 5 m

g = 9.8 m/s^2

T1 = 4.49 s.

F1 = 1/T1

= 0.22 hz.

For pendulum 2,

L = 1 m

g = 9.8 m/s^2

T2 = 2 s

F2 = 1/T2

= 0.5 hz.

Pendulum 2.

The shorter the string, the shorter the period. So the shorter one will have a higher frequency.

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

cant without the picture! ?