In a double-slit experiment the distance between slits is 5.5 mm and the slits are 1.0 m from the screen. Two interference patterns can be seen on the screen: one due to light with wavelength 480 nm, and the other due to light with wavelength 565 nm. What is the separation on the screen between the third-order (m)?

The separation on the screen between the third-order (m) is 46.36 μm

Explanation:

Given

Distance between slits is = 5.5 mm

a = 5.5 mm

Distance between slits and screen is 1.0 m

D = 1.0 m

Wavelength

y1 = 480 nm and y2 = 565 nm

imy1 = m *

imy2 = m *

when m = 3 (third-order)

Δi = i3y2 - i3y1 = 3 *

Δi = 46.36 μm

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explanation:

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2