A cylinder contains 12liters of O2 at 20°c and 15atm. The temperature is raised to 35°c and volume is reduced to 8.5L. Calculate the final pressure. What will be the new pressure if the volume is doubled

Explanation:

According to gas equation  P₁V₁/T₁ = P₂V₂/T₂

Where P₁ is the initial pressure , V₁ is the initial volume and T₁ is the initial temperature

P₂ is the final pressure , V₂ is the final volume and T₂ is the final temperature

Thus P₁ = 15 atmosphere  , V₁ = 12 liters and T₁ = 273 + 20 = 293 K

P₂ = ? , V₂ = 8.5 liters , T₂ = 273 + 35 = 308 K

From gas equation P₂ = P₁V₁T₂/T₁V₂ = 15 x 12 x 308/ 293 x 8.5

= 22.3 atmosphere .

If the volume is doubled

The gas equation will be P₁V₁ = P₂V₂ ;  because temperature is constant

Here V₂ = 2 V₁  therefore  pressure P₂ = P₁/2 = 22.3/2 = 11.1 atmosphere

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.