Answers: 1
is the equivalent height given as 
is the area of the OA part of the door which is calculated as follows:
![F_1=0.6\rho g[h+0.3]](/tpl/images/0512/2418/ef7e5.png)
![F_2=0.4\rho g[h+0.8]](/tpl/images/0512/2418/7f977.png)
![\bar{y}_a=\bar{h}+\frac{I}{A\bar{h}}\\\bar{y}_a=h+0.3+\frac{\frac{1}{12}\times 0.6^3 \times 1}{0.6 \times[h+0.3]}\\\bar{y}_a=h+0.3+\frac{0.03}{h+0.3}](/tpl/images/0512/2418/4b15a.png)
![\bar{y}_b=\bar{h}+\frac{I}{A\bar{h}}\\\bar{y}_b=h+0.8+\frac{\frac{1}{12}\times 0.4^3 \times 1}{0.4 \times[h+0.8]}\\\bar{y}_b=h+0.8+\frac{0.0133}{h+0.8}](/tpl/images/0512/2418/c48e8.png)
=0.4\rho g[h+0.8](0.2+\frac{0.0133}{h+0.8})\\0.6[h+0.3](0.3-\frac{0.03}{h+0.3})=0.4[h+0.8](0.2+\frac{0.0133}{h+0.8})\\0.18h -0.054-0.018=0.08h+0.064+0.00533\\h=0.337 m](/tpl/images/0512/2418/a7f88.png)
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