The voltage across a membrane forming a cell wall is 80.0 mV and the membrane is 10.00 nm thick. What is the electric field strength? You may assume a uniform electric field.

E= 8*10^5 V/m

Explanation:

solution:

electric field strength=v/d

given:

V=80 mV

d= 10 nm=10*10^-9 m

E=80 mV/10*10^-9 m

E= 8*10^5 V/m

8.00 x 10⁶ V/m

The voltage(V) across the membrane is related to the electric field strength (E) and the thickness (d) of the membrane as follows;

V = E x d          (i)

Where, according to the question;

V = 80.0mV = 80.0 x 10⁻³V

d = 10.00nm = 10.00 x 10⁻⁹m

Substitute these values into equation(i) to give;

80.0 x 10⁻³ = E x 10.00 x 10⁻⁹

Solve for E;

E = 80.00 x 10⁻³ / 10.00 x 10⁻⁹

E = 8.00 x 10⁶ V/m

Therefore, the electric field strength is 8.00 x 10⁶ V/m

it becomes positively charged by charging it