Suppose 310. grams of ethanol (ethyl alcohol) is in an aluminum cup of 90.0 grams. Both of these are at 30.0C. A mass m of ice at – 8.5C is taken from a freezer and added to the alcohol in the cup. The final temperature of all the components is 18.0C. Assuming no heat was lost from the system, calculate the mass m of the ice added.

Explanation:

Given

mass of ethanol

mass of aluminium cup

both are at an initial temperature of

specific heat of ethanol

specific heat of aluminium

specific heat of ice

specific heat of water

Latent heat of fusion

suppose m is the mass of ice added

Heat loss by Al cup and ethanol after is reached

Heat gained by ice such that ice is melted and reached a temperature of

Comparing 1 and 2 we get

Thus 23.65 gm of ice is added

the first, second, and fifth options

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