A race car rounds one end of a speedway. This end of the track is a turn with a radius r of approximately 187 ft. If the track is assumed to be completely flat and the race car is traveling at a constant 65.00 mi/h around the turn, what is the race car's centripetal (radial) acceleration a c ?

the centripetal acceleration of the race car is found to be 48.6 ft/s².

Explanation:

The centripetal acceleration of a body performing a circular motion is given by the following formula:

Centripetal Acceleration = ac = v²/r

where,

r = radius of the circular path (track) = 187 ft

v = speed of the body (car) = 65 mi/h

converting it to ft/s:

v = (65 mi/h)(5280 ft/1 mi)(1 h/3600 sec)

v = 95.33 ft/s

therefore,

ac = (95.33 ft/s)²/187 ft

ac = 48.6 ft/s²

Thus, the centripetal acceleration of the race car is found to be 48.6 ft/s².

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.