A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark appear behind it . 5 seconds later the fish is swimming in the same direction at a speed of 2.5 m/s What is the fish, s acceleration

A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark appear behind it. 5 seconds later the fish is swimming in the same direction at a speed of 2.5 m/s, the fish's acceleration - 0.4 m/s squared.

Given:

time t = 5.0 s

Inititial velocity - 0.5 m/s

Final velocity = 2.5 m/s

accelaeration a= ?

Solution:

Placing the given values:

=>

=> = 0.4 m/s squared

Thus, A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark appear behind it. 5 seconds later the fish is swimming in the same direction at a speed of 2.5 m/s, the fish's acceleration - 0.4 m/s squared.

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0.4 m/s²

Explanation:

Given:

v₀ = 0.5 m/s

v = 2.5 m/s

t = 5 s

Find: a

v = at + v₀

2.5 m/s = a (5 s) + 0.5 m/s

a = 0.4 m/s²

i think it would be 5