3. A tennis ball is hit back and forth between two players. If it takes 2.3 s for
the ball to go from one player to the other, what are the period and
frequency of the ball's motion?

Time period of ball's motion is 4.6 s

Frequency of ball's motion is 0.22 Hz

Explanation:

In this problem, Time period is define as the time taken by the ball to come back to its original position.

Let A be the player who first hits the ball towards the player B. We know that ball takes 2.3 s to travel from player A to player B. It takes same time to come back to player A from player B. Thus,

Time period of ball's motion = 2 x 2.3 s = 4.6 s

Frequency is defined as the occurrence of any event per unit time. In this case, the frequency of the ball's motion is given by :

Frequency =

Frequency = = 0.22 Hz    

conservation of mass

mass before something happens = mass afterwards

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft