Calculate the electric field (magnitude and direction) at the upper right corner of a square 1.22 m on a side if the other three corners are occupied by 2.40×10−6 C charges. Assume that the positive x-axis is directed to the right.

Explanation:

It is mentioned that the magnitude of given charge is and side of the square is 1.22 m.

Hence, we will calculate the electric field due to charge at point A as follows.

                        =

                       = (acts along y-axis)

Electric field at D due to the charge at C is as follows.

                        =

                       = (acts along y-axis)

Electric field at D due to the charge at B is as follows.

                        =

                       =

Now, we will resolve it into two components.

Now, the resultant x component is as follows.

Resultant y component is given as follows.

Therefore, resultant electric field at point D is as follows.

                  =

                  =

And, the direction of electric field is

                        =

                         =

This means that net electric field makes an angle of with positive x-axis in counter clockwise direction.

dang that balls went far