A projectile is shot from the edge of a cliff 160 m above ground with an initial speed of 55.0 m/s at an angle of 40° below the horizontal. How much time does it take the projectile to hit the ground?

Time of flight =3.61secs

Explanation:

To find time the projectile hits the ground we must find maximum height

H= U^2sin^2theta/2g

H = 55^2×sin^240°/2×9.8

H= 3025×0.4132/19.6 = 63.77

T= sqrt(2H/g)=

T= sqrt 55×2/9.8

T= sqrt13.05

T= 3.61secs

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