What is the uncertainty in the position of an electron moving at 9.00 × 10 6 m/s with an uncertainty of Δ v = 0.01 × 10 6 m/s ?

The uncertainty in the position of the electron is 5.787 nm

Explanation:

Δx ≥ h/(4πmΔv)

where;

h is Planck's constant and m is the mass of the object.

Planck's constant = 6.626 X 10⁻³⁴

The mass of an electron is 9.11 x 10⁻³¹kg.

Δv is the change in velocity  0.01 × 10⁶ m/s

Δx ≥ h/(4π*mΔv)  = (6.626 X 10⁻³⁴)/(4π*9.11 x 10⁻³¹ *0.01 × 10⁶)

Δx ≥ 5.787 X 10⁻⁹ m

Δx ≥ 5.787 nm

Therefore, the uncertainty in the position of the electron is 5.787 nm

an ion is a charged atom or molecule. it is charged because the number of electrons do not equal the number of protons in the atom or molecule. an atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom.

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.