To keep with the law of conservation of matter, determine the correct product for the following reaction:

PbCl2 (aq) + 2 KI (aq) → +

A) PbI2 + KCl2
B) PbI2 + 2 KCl
C) 2 PbI + KCl2
D) 2 PbI + 2 KCl

B) PbI2 + 2 KCl

Explanation:

To keep the the law of conservation of matter, the equation given above must be balanced i.e the total element in the reactant must be equal to the total elements in the product.

Given the equation

PbCl2 (aq) + 2 KI (aq) →

At the reactant shown, there are one mole of lead Pb, 2 moles of chlorine Cl, 2moles of Potassium K and 2 moles of Iodine.

During reaction, the Chlorine atom will react with the potassium atom K and the lead atom Pb will react with the iodine atom.

The resulting product that will balance the chemical equation is

PbI2 + 2 KCl

The equation will then become

PbCl2 (aq) + 2 KI (aq) → PbI2 + 2 KCl

If we look at both sides of the equation, we will see that all the elements have the same number of atoms.

true

explanation:

double the distance = divide strength by 4