A pendulum of mass 240 g undergoes simple harmonic motion when acted upon by a force of 14 N. The pendulum crosses the point of equilibrium at a speed of 6 m · s−1. What is the energy (in J) of the pendulum at the center of the oscillation?

4.3J

Explanation:

The energy associated with a simple pendulum is the potential energy and the kinetic energy. At rest the kinetic energy is zero while the potential energy is maximize, also at the center of the oscillation, the potential energy is zero while the kinetic energy is maximize.

Hence from the question given, we can conclude that the only associated energy is the Kinetic energy which is expressed  as

since mass,m=240g=0.24kg,

Velocity V=6m/s

If we substitute values we arrive at

be subject to a force andchange its motion

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards