A dog sits 1.22 m from the center of a merrygo-round with an angular speed of 1.07 rad/s. If the magnitude of the force that maintains the dog’s circular motion is 32.3 N, what is the dog’s mass?

24.74 kg

Explanation:

The formula of centripetal force is given as

F = mv²/r Equation 1

Where F = Force, m = mass of the dog, v = velocity of the dog, r = radius of the circle

Also,

v = ωr Equation 2

ω = angular velocity

Substitute equation 2 into equation 1

F = m(ωr)²/r

F = mω²r Equation 3

Make m the subject of the equation,

m = F/ω²r Equation 4

Given: F = 32.3 N, r = 1.22 m, ω = 1.07 rad/s

Substitute into equation 4

m = 32.3/(1.22×1.07)

m = 24.74 kg.

Thus the mass of the dog = 24.74 kg

terd muffin is the correct answer

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.