In which direction is the electric field on the cylindrical gaussian surface?

outward.

Explanation:

The electric field of an infinite cylindrical conductor with a uniform linear charge density can be obtained by using Gauss' law. Considering a Gaussian surface in the form of a cylinder at radius r > R, the electric field has the same magnitude at every point of the cylinder and is directed outward. The electric flux is then just the electric field times the area of the cylinder.

It can be expresed

ФE2πrL=

λ= charge per unit length

the answer is b i think

answer; equivalent to a one(1) horsepower motor;