The coefficients of friction between the 20-kg crate and the inclined surface are µ,8 = 0.24 and J. lk = 0.22. If the crate starts from rest and the horizontal force F = 200 N, what is the magnitude of the velocity of the crate when it has moved 2 m?

5.60 m/s

Explanation:

Given

Coefficient of static friction

Coefficient of kinetic friction

mass of crate

Force applied

maximum static Friction

thus applied force is greater than Static friction therefore kinetic friction will come into play

net Force on crate

Magnitude of velocity can be obtained by using

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

here initial velocity is zero as crate start from rest

c) up

hope this