Two uniformly charged conducting plates are parallel to each other. They each have area A. Plate #1 has a positive charge Q while plate #2 has a charge −3 Q.
Using the superposition principle find the magnitude of the electric field at point P in the gap.
1. E =5Q / εoA
2. E = 4Q/εoA
3. E =3Q/ εoA
4. E =Q/ εoA
5. E =2Q/ εoA

5

Explanation:

Given

First Plate has a charge of +Q  and area A

Second Plate has a charge of -3 Q and area A

We Know electric Field due to sheet charge is given by

Where Q=charge over the Plate

A=Area of plate

= Permittivity of free space

Electric Field Due to Positive charge will always be away from it while for negative charge it is towards it.

Net Electric Field at a point between between the Plates is the superimposition of two electric with direction

Net electric Field is towards the negative charged plate

answer; i believe the correct answer is (40,000 j) good luck

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.