An object is thrown directly upwards from the ground at a velocity of 9ms. Recalling that the acceleration due to gravity is −gms2, find the time at which the object reaches its maximum height. What is this maximum height? Your answers should be in terms of g.

Explanation:

Given

Object is thrown with a velocity of

Acceleration due to gravity is -g (i.e. acting downward)

Vertical distance traveled by object is given by

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

at maximum height final velocity is zero

time taken to reach maximum height

using

v=u+at

0=9-gt

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explanation:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.