Physics, 12.02.2020 00:31 sanchitcoolcham7362
When a point mass m with charge q is constrained to move along a frictionless line (up and down) with a charge Q at the botton with the same sign as q. Show that the particle is in equilibrium at position y0 = p kqQ=(mg).
Answers: 2
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What happens to the velocity of the car when the upward pull of the cable is greater than the downward pull of gravity as the car rises toward the top?
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When a point mass m with charge q is constrained to move along a frictionless line (up and down) wit...
History, 21.10.2020 19:01