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Physics, 11.02.2020 04:29 maxwellirowa10oy9yaf
At time t = 0 an elevator starts moving upward from the ground at a constant speed vo. At a later time t = T1 = 2.35s a marble is "let go" through the floor. In other words, imagine a marble resting on the floor of the elevator and a trap door of sorts opening up from under the marble. The marble then hits the ground at a still later time t = T2 = 11.2s.
1. What is the maximum height (above the ground) that the marble reaches in this process?
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At time t = 0 an elevator starts moving upward from the ground at a constant speed vo. At a later ti...
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