A fish swimming behind an oil tanker gets caught in a whirlpool created by the ship’s propellers. The fish has an initial angular speed of 0.70 rad/s. After 4.3 s, the fish’s angular speed is 13.7 rad/s. If the water in the whirlpool accelerates at a constant rate, what is the angular acceleration? Answer in units of rad/s 2 .

3.02 rad/s²

Explanation: The motion of the fish is of a constant angular acceleration, hence it motion can be described by using the equation of motion of a constant angular acceleration.

ω = ω' + αt

Where ω = final angular speed= 13.7rad/s ω'= initial angular speed= 0.7rad/s α = angular acceleration =?

time= 4.3s

13. 7 = 0.7 + (4.3)α

13.7 - 0.7 = 4.3α

13 = 4.3α

α = 13/ 4.3

α = 3.02 rad/s²

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation:

wavelength divides in half and speed stays the same.