The range of a projectile depends not only on v0 and θ but also on the value g of the free-fall acceleration, which varies from place to place. in 1936, jesse owens established a world's running broad jump record of 8.09 m at the olympic games at berlin (where g = 9.8128 m/s^2). assuming the same values of v0 and θ, by how much would his record have differed if he had competed instead in 1956 at melbourne (where g = 9.7999 m/s2)?

ΔR = 1.06cm

Explanation:

Given;

R₁= 8.09m

g₁ = 9.8128m/s^2

g₂ = 9.7999m/s^2

The range of a projectile is given as

R = (v²sin2θ)/g

The range at the Olympic Games at Berlin is;

R₁ = (v₀²sin2θ)/g₁

The range at Melbourne is

R₂ = (v₀²sin2θ)/g₂

Change in the range is;

ΔR = R₂ - R₁ = (v₀²sin2θ)/g₂ - (v₀²sin2θ)/g₁

ΔR = (v₀²sin2θ)(1/g₂ - 1/g₁)

ΔR = (v₀²sin2θ/g₁)(g₁/g₂ - 1)

ΔR = R₁(g₁/g₂ - 1)

Substituting the given values;

ΔR = 8.09(9.8128/9.7999 - 1)

ΔR = 0.0106m

ΔR = 1.06cm

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