How much heat must be removed from 0.175 kg of water to lower its temperature from 24.3°c to 5.00°c? (unit = j)

14185.5J

Explanation:

Thermal energy can be calculated using the formula

Q = mcT where

Q is the amount of thermal energy in J

m is the mass in kg

c is the specific heat capacity in J/kg/C

T is the change in Temperature in C.

Hence by applying this formula, we get:

Q = (0.175)(4200)(24.3 - 5.00)

Q = 14185.5 J

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.