Two particles, one with charge − 3.77 μc −3.77 μc and one with charge 4.39 μc, 4.39 μc, are 4.34 cm 4.34 cm apart. what is the magnitude of the force that one particle exerts on the other?

the magnitude of the force that one particle exerts on the other is 79.08 N

Explanation:

given information:

q₁ = 3.77 μC = -3.77 x 10⁻⁶ C

q₂ = 4.39 μC = 4.39 x 10⁻⁶ C

r = 4.34 cm = 4.34 x 10⁻² m

What is the magnitude of the force that one particle exerts on the other?

lFl = kq₁q₂/r²

   = (9 x 10⁹) (3.77 x 10⁻⁶) (4.39 x 10⁻⁶)/(4.34 x 10⁻²)²

   = 79.08 N

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

a is the best answer your welcome