The two naturally occurring isotopes of hydrogen are (atomic mass = 1.00783 ; abundance 99.9885%) and (atomic mass = 2.01410 ; abundance 0.0115%). a)how many peaks will the mass spectrum have? b) give the relative atomic masses of each of these peaks. c) which peak will be the largest and which the smallest?

A) The number of peaks that the mass spectrum will have is; 3 peaks

B) The relative atomic masses of each of the peaks are;

Peak 1H - 1H = 2.01566 amu

Peak 1H - 2H = 3.02193 amu

Peak 2H - 2H = 4.02820 amu

C) The largest and smallest peak will be;

Largest Peak = Peak 2H - 2H

Smallest Peak = Peak 1H - 1H

We are told that the two naturally occurring isotopes of hydrogen are;

atomic mass = 1.00783 ; abundance 99.9885%

atomic mass = 2.01410 ; abundance 0.0115%

A) The mass spectrum will have 3 peaks namely;

B) The relative atomic masses of each of the peaks will be;

Relative atomic mass of Peak 1H - 1H = 1.00783 + 1.00783 = 2.01566 amu

Relative atomic mass of Peak 1H - 2H = 1.00783 + 2.01410 = 3.02193 amu

Relative atomic mass of Peak 2H - 2H = 2.01410 + 2.01410 = 4.02820 amu

C) From B above, we conclude that;

Largest Peak is Peak 2H - 2H

Smallest Peak is Peak 1H - 1H

Read more on relative atomic mass of peaks in mass spectrum at; link

a)  two peak in the spectrum , b)  m₁ / m_ c = 100783 , m₂ / m_c = 2.01410, c)  the lighter isotope peak is much higher than the other

Explanation:

A mass spectrometer is a device where an ionized and accelerated sample in a constant electric field enters a magnetic field that deflects it for detection, in vernal the intensity of the magnetic field is controlled.

Newton's second Law gives us

                   = m a

The acceleration is centripetal

                   a = v² / r

                   q v B = m v² / r

                   q B = m v / r

                   r = (m / q) v / B

a) with We have two different isotopes must separate only two peak in the spectrum

b) the relative atomic mass is the ratio between the mass of an atom in kg and the weighted mass of carbon that is 12

          m₁ / m_ c = 100783

          m₂ / m_c = 2.01410

It has units for being the relationship between two masses

c) The peak height intensity is proportional to the abundance of each isotope.

       The most used is to calculate the relative abundances is to use the area of each peak

        Therefore the lighter isotope peak is much higher than the other

force tends to be low and long diustance masses are high

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