The cubit is an ancient unit of length based on the distance between the elbow and the tip of the middle finger of the measurer. assume that the distance ranged from 43 to 53 cm, and suppose that ancient drawings indicate that a cylindrical pillar was to have a length of 6.0 cubits and a diameter of 1.0 cubits. for the stated range, what are the lower values for

(a) the cylinder's length in meters,
(b) the cylinder's length in millimeters, and
(c) the cylinder's volume in cubic meters

(a) upper : 3.18 m, lower: 2.58

(b) upper : 3180 mm, lower: 2580 mm

(c) upper : 2.81 m³, lower: 1.5 m³

Explanation:

given information:

the distance ranged from 43 to 53 cm

length of cylindrical pillar = 6 cubits

diameter = 1 cubit

(a) the cylinder's length in meters

upper = 53 cm x 6 cubits

          = 318 cm

          = 3.18 m

lower = 43 cm x 6 cubits

         = 258 cm

         = 2.58 m

(b) the cylinder's length in millimeters

upper = 3.18 m

          = 3180 mm

lower = 2.58 m

          = 2580 mm

(c) the cylinder's volume in cubic meters

upper : V = πr²l

                = π (0.53m)² (3.18)

                = 2.81 m³

lower : V = πr²l

                = π (0.43m)² (2.58)

                = 1.5 m³

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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v=ir = 3x15 =45 v