An electric field can induce an electric dipole in a neutral molecule (or atom) by pushing the positive and negative charges inside the molecule in opposite directions. the dipole moment of the induced dipole is directly proportional to the electric field at the molecule. that is, p=αe , where p is the induced dipole moment, α is called the polarizability of the molecule, and e⃗ is the electric field at the molecule. a stronger electric field at the molecule results in a more polarized molecule and causes a larger dipole moment p . a molecule with a larger polarizability, α, will be more polarized when subjected to the same electric field. find an expression for the magnitude of the force f⃗ ionondipole. express your answer in terms of the variables q, r, α and appropriate constants.

F is the electric force, q is the dipole charge, E is the electric field intensity, p is dipole moment, ∆ represent polarizability

F = qE. p = ∆E.

Therefore F(The magnitude of force) = (q*p)/∆.

Note the ∆ is used to denoted alpha here

Explanation:

Useful Explanation

The derived electrostatic forces act on the end charges of the dipole. Because the electric field is uniform, those forces act in opposite directions and with the same magnitude

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards