An electron and a proton are each placed at rest in a uniform electric field of magnitude 560 n/c. calculate the speed of each particle 46.0 ns after being released. electron 4.5e^-6 incorrect.

The speed of electron is and the speed of proton is 2468.02 m/s.

Explanation:

Given that,

Electric field, E = 560 N/C

To find,

The speed of each particle  (electrons and proton) 46.0 ns after being released.

Solution,

For electron,

The electric force is given by :

Let v is the speed of electron. It can be calculated using first equation of motion as :

u = 0 (at rest)

For proton,

The electric force is given by :

Let v is the speed of electron. It can be calculated using first equation of motion as :

u = 0 (at rest)

So, the speed of electron is and the speed of proton is 2468.02 m/s. Therefore, this is the required solution.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr