What is the force felt by the electrons and the nuclei in the rod when the external field described in the problem introduction is applied? (ignore internal fields in the rod for the moment.)a) both electrons and nuclei experience a force to the right.
b) the nuclei experience a force to the right and the electrons experience a force to the left.
c) the electrons experience a force to the left but the nuclei experience no force.
d) the electrons experience no force but the nuclei experience a force to the right.

(B). nuclie experiences a force to the right and electron experiences a force to the left.

Explanation: The nuclie is positively charged and so it will experience a force in the same direction as the direction of the Electric Field {in this case to the right}

On the otherhand, the electrons which are negatively charge will experience a force in opposite direction to that experienced by the nuclie which is positively charged. So the electron experiences a force to the left.

I believe this is clear.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft