The length of the assembly decreases by 0.006 in. when an axial a- force is applied by means of rigid end plates. determine

(a) the magnitude of applied force,
(b) the corresponding stress in the steel core.

(a) The magnitude of the applied force is (0.0001524k) Newton

(b) Corresponding stress in the steel core = (0.0001524k/area) Newton per meter square

Explanation:

(a) From Hookes law of elasticity,

Force applied = force constant (k) × compression

compression = 0.006 in = 0.006 × 0.0254 = 0.0001524 meter

Force applied = k × 0.0001524 = (0.0001524k) Newton

(b) Stress = Force applied (Newton)/area of steel core (meter square) = (0.0001524k/area) Newton per meter square

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