Three identical uniform bricks of mass m and length l are stacked on top of each other. (a) what is the maximum distance d so that the stack does not tumble over? (hint: consider the top two bricks first, then add the bottom brick) (b) what is the maximum distance d that can be achieved by optimal stacking of an infinite number of bricks?

Explanation:

Given

Three blocks are placed over each other at a certain distance.

Center of gravity of each block is at distance of 0.5 L from one end of block.

First We consider block 1 and 2

Block 1 center of gravity will try to tumble the block 1 if center of gravity torque goes beyond 0.5 L of second block.

i.e. maximum distance up to which block 1 is placed over block 2 is

combined center of gravity of 1 and 2 is

Center of gravity

Now consider block 2 and 3

Combined center of gravity of  block 1 and 2 will tumble over when their Center of gravity goes beyond edge of block 1

i.e. maximum value of

(b) As the no of blocks increases center of gravity increases so maximum value of

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.

i would say