Find the force required to keep a 3000 lb car parked on a hill that makes an angle of 15 degrees with the horizontal.

3462.3N

Explanation:

3000 lbs = 3000 / 2.2 = 1363.6kg

Let g = 9.81 m/s2. The weight of the car is

W = mg = 1363.6*9.81 = 13377 N

Since the car is parked on a hill that makes an angle of 15 degrees with the horizontal, the gravity force that is parallel with the road is

Wsin(15) = 13377*0.2588 = 3462.3 N

Which is also the force that is required to keep the 3000lb car stationary.

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge