Physics, 23.01.2020 00:31 neelydeY23

Arope is lying on the floor and has a mass which applies a force of 3 n/m. how much work is required to raise one end of the rope to a height of 2 meters?

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Answer from: chjam265

The work required to raise one end of the rope to a height of 2 meters with an applied force of 3 N is 6 joules.

We can calculate the work required to raise one end of the rope to a height of 2 meters as follows:

$W = F*d*cos(\theta)$

Where:

F: is the force exerted = 3 N (newton: unit of force)

d: is the displacement = 2 m

θ: is the angle between the applied force and the displacement

Since the force and the displacement are in the same direction, θ = 0, so:

$W = F*d*cos(\theta) = Fdcos(0) = F*d$

Hence, the work done is:

W = 3 N*2m = 6 J

Therefore, it is required 6 J of work.

You can see another example of work calculation here: link

I hope it helps you!

Answer from: 76022sfox

At least 6 N, assuming that the rope has a length of more than 2 meters.

Explanation:

In general, if it takes a force of F(h) newtons to lift an object at height , the work done lifting the object from h = a to h = b can be found using the definite integral about :

$\displaystyle W = \int \limits_{a}^{b} F(h)\, dh$ .

If the value of F(h) is a constant $m \cdot g$ regardless of height , then the result of the integral would be

$\displaystyle \int \limits_{a}^{b} (m \cdot g)\, dh = \left[m \, g\, h \right]_a^b = m\cdot g \, (b - a)$ .

However, in this case the value of F(h) does depend on the value of .

At height $h = 0\; \rm m$ , nothing is being lifted. The amount of force required would be zero. At height $h = 1\; \rm m$ , one meter of the rope is in the air. That requires a force of at least $1\; \rm m \times 3\; N \cdot m^{-1} = 3\; N$ .In general, at a height of

meters, the force required would be at least $3\, h$ Newtons.

In other words, $F(h) = 3\; h$ where is in Newtons and is in meters.

Evaluate the integral:

$\begin{aligned} W &= \int \limits_{a}^{b} F(h)\, dh \cr &= \int \limits_{0}^{2}3\, h \, dh && \text{Apply the power rule.}\cr &= \left[\frac{3}{2}\,h^2\right]_{0}^{2}\cr &= \frac{3}{2} \times 2^2 \cr &= 6\end{aligned}$ .

Arope is lying on the floor and has a mass which applies a force of 3 n/m. how much work is required

Answer from: Quest

Answer: buoyancy forceexplanation: in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

Answer from: Quest

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