An aircraft has a net excess thrust of 14,000 lbs and weighs 36,000 lbs. if it starts from 30 kts, what is its velocity (in knots) after 15 seconds?

"(witch the answer is 141.218) you need this for the net part"

how many feet down the runway would the aircraft in problem 4 be at rotation if vr = 160 kts? (the aircraft is at 135 feet down the runway when it starts its takeoff and starts from 30kts)

Ibelieve the answer is either b or c, but i'm leaning more towards c.hope my answer has you : )

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

Chromium  +  hydrogen sulfate  =  chromium(iii) sulfate  +  hydrogenso then it will be  a. cr + h2so4? cr2(so4)3 + h2