The coffee machine heats water from 20 °c to 90 °c.
the power output of the coffee machine is 2.53 kw.
the specific heat capacity of water is 4200 j/kg °c.
calculate the mass of water that the coffee machine can heat in 14 seconds.

The mass of water that the coffee machine can heat in 14 seconds is equal to 0.1204 kg.

Given:

Initial temperature of water =

Final temperature of water =

Power of coffee machine =

Specific heat capacity of water =

Time for which water is heated =

Mass of water = m = ?

Power is defined as work done in unit time. Let the heat energy be Q. Power (P) is defined as where t denotes the time for which energy is supplied. Q can be rewritten as:

......................(1)

Formula for Heat energy is given by

Q = m×c×Δt ........................................(2)

where:

Q = Heat energy (in J)

m = mass of the substance being heated in grams(kg)

c = the specific heat of the substance in J/(kg.°C)

Δt = Change in temperature (in °C)

Δt = (Final temperature - Initial temperature) = .......................(3)

From (1) and (3), solving equation (2) for m;

Q = m×c×Δt

The mass of water that the coffee machine can heat in 14 seconds is equal to 0.1204 kg.

an energy transformation flow diagram is shown

where is it ?

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!