Asolid sphere of mass 0.6040 kg rolls without slipping along a horizontal surface with a translational speed of 5.080 m/s. it comes to an incline that makes an angle of 33.00° with the horizontal surface. to what vertical height above the horizontal surface does the sphere rise on the incline?

1.315 m

Explanation:

Assumption: there is no resistance of any type

v= 5.08 m/s

g = 9.81m/s^2

change in kinetic energy = change in gravitational potential energy

mass on both side is same so it cancels out

and also making 'h' alone on one side

h= ((5.08)^2)/(2*9.81)

 h =1.3153m

b. latent learning (the word "latent" itself means something that exists but isn't obvious, only under certain conditions! )

number of electrons for neutral cl