A0.10 g honeybee acquires a charge of +23 pc while flying.
a. the electric field near the surface of the earth is typically 100 n/c, directed downward. what is the ratio of the electric force on the bee to the bee's weight?
b. what electric field strength and direction would allow the bee to hang suspended in the air?

a)

b) parallel to the earth surface.

Explanation:

Given:

mass of the bee,

charge acquired by the bee,

a.

Electrical field near the earth surface,

Now the electric force on the bee:

we know:

The weight of the bee:

Therefore the ratio :

b.

The condition for the bee to hang is its weight must get balanced by the electric force acing equally in the opposite direction.

So,

parallel to the earth surface.

a.

explanation:

he kicked it 10 feet straight up into the air? i think this works.