Question 7 (5 points)
blaine steps onto a ski slope with an angle of 25°. there is a coefficient of kinetic friction of
0.75 between him and the ground. he has a mass of 65 kg.
b. write the expressions for net force in the x and y directions be sure to tilt your axis along the incline
c. calculate the net force and acceleration in the x and y directions

The net force is 165N an the the acceleration is 2.5 m/s2

Explanation: First find the component of force with respect to the angle of inclination.

F = mgsin (theta) = 65 kg x 9.8 m/s2 x sin (25°) = 286N

Next find the value of the normal force

N = mgcos ( theta)

= 65 kg x 9.8m/s² x cos (25°)

= 577N

Substitute the Value of N to find the frictional force.

fk= Coeffiecient of kinetic friction x N

= 0.75x 577 N = 433 N

Solve for the net force through summation of forces.

433 N - 268N = 165N

To find a. Use F= ma

Derive so that a= F/m

a= 165N / 65kg

= 2.54 m/s2

layer a is the exosphere and layer b is the thermosphere.   is the answer i think but i hope this .

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.