Apoint charge q1 = 3.0 µc is at the origin and a point charge q2 = 6.0 µc is on the x axis at x = 10 m.
(a) find the electric force on charge q2.
12 = mn
(b) find the electric force on q1.
21 = mn
(c) what would your answers for parts (a) and (b) differ if q2 were -6.0 µc?
12 = mn
21 = mn

a.

b.  

c. ,  

Explanation:

Recall that like charged particles repel while unlike charges attract. hence we can conclude that both particles will repel with a force of magnitude

Where .

Substituting values into the above equation we have

Hence the electric force on charge q2 is of magnitude  and the direction is away from q2 in the positive x direction  which can be represented as a vector form as

.

bTo determine the electric force on charge q1, the magnitude remain the same

.. but in the opposite direction which is the negative x-axis

c.if the q2 is -6.0uc, the magnitude of the force will be the same but the direction will be different since both charges are unlike, hence the electric force on q 2 as in (a) above will be towards q1  which can be represented as a vector form as

and for the second case scenario the forc will be directed towards the second charge which can be represented as  

b.transmitters send radio waves, and receivers capture radio waves.

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.