1.
a 4 kg object is moving 15 m/s to the right. a 6 n force
pushes for 5 seconds to the left.
a. how much momentum does it start with?
b. how much impulse acted on the object?
c. what is it's change of momentum?
d. under the diagram, calculate the final velocity of the object.

Correct A. p₁ = 60 kg m/s , B. p₂ = 30 kg m/s , C. Δp = 30 kg m/s

D.  V = 7.5 m/s

Explanation:

A. The impulse (momentum) formula is p₁ = m · V = 4 · 15 = 60 kg m/s

B. The second impulse formula is p₂ = F · Δt = 6 · 5 = 30 kg m/s

C. The change of impulse is Δp = p₁ - p₂ = 60 - 30 = 30 kg m/s

D. The final velocity is V = Δp / m = 30 / 4 = 7.5 m/s

God is with you!!!

the answer is b i think

the answer is 3.1 his answer is wrong mines is right