A16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head-on collision with a 14.0 kg raft moving to the right at 16.0 m/s. after the collision, the raft moves to the left at 14.4 m/s. disregard any effects of the water. find the velocity of the can

14.1 m/s

Explanation:

given,

mass of canoe, M = 16 Kg

initial speed in left, u = 12.5 m/s

mass of raft. m = 14 Kg

initial speed of raft in right, v = -16 m/s

taking right direction as negative

after collision

speed of raft, v' = 14.4 m/s

speed of canoe,u' = ?

using conservation of momentum

M u + m v = M u' + m v'

16 x 12.5 + 14 x (-16) = 16 x u' + 14 x 14.4

16 u' = -225.6

u' = -14.1 m/s

negative sign represent the velocity is in left direction.

speed of the Canoe after collision is equal to 14.1 m/s

positive reinforcement? ?

we need to know the time interval during which the force acts. impulse of force = momentum change