Asoccer ball is kicked from the ground at an angle of θ = 42 degrees with respect to the horizontal. the ball is in the air for a time tm = 1.3 s before it lands back on the ground. numerically, what is the total horizontal distance, dm in meters, traveled by the ball in the time, tm?

Explanation:

Given

Launch angle

time period of flight

Time period of Projectile

Where u=initial velocity

g=acceleration due to gravity

Range of Projectile is given by

The total horizontal distance covered by ball is of 9.17 m.

Given data:

The angle with respect to the horizontal is, θ = 42 degrees.

The time of flight of ball is, t = 1.3 s.

The concept of projectile motion is applied to solve this problem. The motion having some inclination is known as projectile motion. So, the time of flight of ball is,

here, u is the initial velocity of ball. Solving as,

Now, the the total horizontal distance covered by ball is called Range. So, the expression for the range is,

Thus, we can conclude that the total horizontal distance covered by ball is of 9.17 m.

Learn more about the projectile motion here:

link

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