To find the magnitude of the normal force, you must express fn in terms of fw since ff is an unknown. using the equations you found in the two previous parts, find an expression for fn involving fw and θ but not ff. cosθff - sinθfn = 0ffsinθ + fncosθ - fw = 0

100 pounds is 100 pounds no matter the object or item being weighed

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j