An air-track glider attached to a spring oscillates between the 13.0 cmcm mark and the 64.0 cmcm mark on the track. the glider completes 15.0 oscillations in 35.0 ss . what are the (a) period, (b) frequency, (c) amplitude, and (d) maximum speed of the glider

To solve this problem we will apply the concepts related to the Period such as the relationship between the time taken to make the oscillations, the frequency as the inverse of the period, the amplitude as the midpoint of the distance traveled and the linear velocity as the product between the velocity angular and amplitude, this is

PART A) The period would be defined by the time it takes to perform the 15 oscillations so the unit value would be

PART B) The frequency as the inverse of the period

PART C) The amplitude as the midpoint of the distance traveled

PART D) The linear velocity is the product between the amplitude and the angular frequency, then

Where

Therefore the linear velocity is

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

reserve is the answer